Skip to main content

Java If-Else conditional statements

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:
Wikipedia if-else flow chart
Source: Wikipedia
Task 
Given an integer, , perform the following conditional actions:
  • If  is odd, print Weird
  • If  is even and in the inclusive range of  to , print Not Weird
  • If  is even and in the inclusive range of  to , print Weird
  • If  is even and greater than , print Not Weird
Complete the stub code provided in your editor to print whether or not  is weird.
Input Format
A single line containing a positive integer, .
Constraints
Output Format
Print Weird if the number is weird; otherwise, print Not Weird.
Sample Input 0
3
Sample Output 0
Weird
Sample Input 1
24
Sample Output 1
Not Weird
Explanation
Sample Case 0:  
 is odd and odd numbers are weird, so we print Weird.
Sample Case 1:  
 and  is even, so it isn't weird. Thus, we print Not Weird.
 import java.io.*;
    import java.util.*;
    import java.text.*;
    import java.math.*;
    import java.util.regex.*;

    public class Solution {

        public static void main(String[] args) {

            Scanner sc=new Scanner(System.in);
            int n=sc.nextInt();            
            String ans="";
            if(n%2==1){
                ans = "Weird";
            }
            else if(n>= 6 && n <= 20){
                 ans = "Weird";
            }
            else{
                    ans = "Not Weird";    
                }
                
               //Complete the code
                
            
            System.out.println(ans);
            
        }
    }

Comments

Post a Comment